On 20/01/2023 15:29, Dino wrote:
let's say I have this list of nested dicts:
[
{ "some_key": {'a':1, 'b':2}},
{ "some_other_key": {'a':3, 'b':4}}
]
I need to turn this into:
[
{ "value": "some_key", 'a':1, 'b':2},
{ "value": "some_other_key", 'a':3, 'b':4}
]
Assuming that I believe the above, rather than the code below, this works:
listOfDescriptors = [
{ ** (L := list(D.items())[0])[1], **{'value' : L[0] } }
for D in origListOfDescriptors]
I believe that from Python 3.9 onwards this can be written more
concisely as:
listOfDescriptors = [
{ (L := list(D.items())[0])[1] } | {'value' : L[0] }
for D in origListOfDescriptors] # untested
Best wishes
Rob Cliffe
I actually did it with:
listOfDescriptors = list()
for cd in origListOfDescriptors:
cn = list(cd.keys())[0] # There must be a better way than this!
listOfDescriptors.append({
"value": cn,
"type": cd[cn]["a"],
"description": cd[cn]["b"]
})
and it works, but I look at this and think that there must be a better
way. Am I missing something obvious?
PS: Screw OpenAPI!
Dino
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