I don't know what flake8 is complaining about, but I think you want a
literal "." character in front of the two "\d" escapes. So "." should
be replaced by "\." in two places. In addition to using a raw string,
that is.
If you may need to detect versions larger than 9 in any position, you
would need to generalize your pattern, since "\d" is only going to look
at a single character, IIUC.
If you could be sure that the version string would always look exactly
like your example, you could avoid a regex by splitting:
_, version = version_string.split('Version:')
version_parts = version.split('.')
That's probably hoping for too much, though.
On 9/10/2022 2:46 PM, c.bu...@posteo.jp wrote:
Hello,
My `flake8` gives me a "W605 invalid escape sequence" [1] warning for
this piece of example code.
import re
def foobar():
rex = re.compile('Version: \d+.\d+.\d+.*', re.MULTILINE)
for match in rex.findall(' Version: 1.2.3 '):
print(match)
if __name__ == '__main__':
foobar()
But running this with Python 3.9.2 makes no problem. Python doesn't
give me a `SyntaxWarning` or anything else. Python doesn't give me an
error or warning. Only `flymake8` gives me this error.
I do understand what is wrong with the pattern string in `compile()`.
There should be a `r''` or the regex-escape characters should be
escaped them selfs (e.g. `'Version: \\d'`).
But my question is about why Python doesn't give me an error about it
and why does it work. The pattern matches. Shouldn't there be an error
or something? Does Python identify this string as an r-String by itself?
[1] -- <https://www.flake8rules.com/rules/W605.html>
--
https://mail.python.org/mailman/listinfo/python-list
