Cecil Westerhof via Python-list schreef op 27/07/2022 om 17:43:
"Michael F. Stemper" <michael.stem...@gmail.com> writes:
> This is orthogonal to your question, but might be of some use to you:
>
> The combination of using len(to_try) as an argument to randint() and
> saving the output to a variable named "index" suggests that you might
> be setting up to select a random element from to_try, as in:
> something = to_try[index]
>
> If that is the case, you might want to consider using random.choice() instead:
>
> >>> from random import choice
> >>> to_try = [2,3,5,7,11,13,"seventeen",19]
> >>> choice(to_try)
> 2
> >>> choice(to_try)
> 'seventeen'
> >>> choice(to_try)
> 13
> >>> choice(to_try)
> 5
> >>>
Yes, I try to select a random element, but it has also to be removed,
because an element should not be used more as once.
This is the code I use:
# index = randbelow(len(to_try))
index = randrange(len(to_try))
found = permutation[to_try.pop(index)]
Do you know in advance how many items you'll need, or maybe an upper
limit on the amount? In that case it might be more efficient to use
random.sample(to_try, k=nr_items_needed).
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