On 05/06/2022 09.50, Chris Angelico wrote: > No, but it shouldn't be too hard to make it if you want it. The > obvious option of calling max/min on the enumerated list won't work on > its own, since the index comes before the value, but with a key > function it would work fine: > >>>> min(enumerate(l), key=lambda x: x[1]) > (0, 1.618033) >>>> max(enumerate(l), key=lambda x: x[1]) > (1, 3.141593)
An elegant solution! But, but, but which of the above characters is an 'el' and which a 'one'??? (please have pity on us old f...s and the visually-challenged!) -- Regards, =dn -- https://mail.python.org/mailman/listinfo/python-list
