Hi, I'm looking for a convenience function to convert a Marshmallow schema into a valid Python class definition. That is, I want to generate python code (class MySchema.. etc) that I could write to a .py file. Does this exist? I tried the code below, but that is not the intended use of marshmallow.Schema.from_dict or inspect.getsource. from inspect import getsource from marshmallow import Schema d = dict(something='potentially', very='complicated') schema = Schema.from_dict(d) python_class_def_as_str = getsource(schema()) # OSError https://marshmallow.readthedocs.io/en/stable/api_reference.html#marshmallow.Schema.from_dict https://docs.python.org/3/library/inspect.html#inspect.getsource Thanks! Albert-Jan -- https://mail.python.org/mailman/listinfo/python-list
