On Sat, 12 Mar 2022 at 22:37, <2qdxy4rzwzuui...@potatochowder.com> wrote:
> Once hashing an object fails, why would an application try again?  I can
> see an application using a hashable value in a hashable situation again
> and again and again (i.e., taking advantage of the cache), but what's
> the use case for *repeatedly* trying to use an unhashable value again
> and again and again (i.e., taking advantage of a cached failure)?

Honestly? Don't know. Maybe because the object is passed to different
functions and all of them independently test the hashability? I'm
clutching at straws.
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