Ok you suggested: >>>items = [1,2,3,4,5,6,7,8,9,0] >>>for item in items[:-1]: >>> print(item)
1 2 3 4 5 6 7 8 9 Does this also work for length = 1? Ok let me try: >>> foo = ["a","b","c"] >>> for x in foo[:-1]: ... print(x) ... a b >>> foo = ["a"] >>> for x in foo[:-1]: ... print(x) ... Oki Doki Mostowski Collapse schrieb am Mittwoch, 15. September 2021 um 23:10:50 UTC+2: > And how do you only iterate over n-1 elements? > I don't need a loop over all elements. > > With array slicing? > > Someting like: > > for item in items[0:len(items)-2]: > ___print(item) > > Or with negative slicing indexes? Problem > is my length can be equal to one. > > And when I have length equal to one, the > slice might not do the right thing? > > LoL > alister schrieb am Mittwoch, 15. September 2021 um 22:00:30 UTC+2: > > for item in items: > > print(item) -- https://mail.python.org/mailman/listinfo/python-list
