On Sat, Sep 11, 2021 at 3:26 PM dn via Python-list <python-list@python.org> wrote: > > On 31/08/2021 01.50, Chris Angelico wrote: > > On Mon, Aug 30, 2021 at 11:13 PM David Raymond <david.raym...@tomtom.com> > > wrote: > >> > >>> def how_many_times(): > >>> x, y = 0, 1 > >>> c = 0 > >>> while x != y: > >>> c = c + 1 > >>> x, y = roll() > >>> return c, (x, y) > >> > >> Since I haven't seen it used in answers yet, here's another option using > >> our new walrus operator > >> > >> def how_many_times(): > >> roll_count = 1 > >> while (rolls := roll())[0] != rolls[1]: > >> roll_count += 1 > >> return (roll_count, rolls) > >> > > > > Since we're creating solutions that use features in completely > > unnecessary ways, here's a version that uses collections.Counter: > > > > def how_many_times(): > > return next((count, rolls) for count, rolls in > > enumerate(iter(roll, None)) if len(Counter(rolls)) == 1) > > > > Do I get bonus points for it being a one-liner that doesn't fit in > > eighty characters? > > > Herewith my claim to one-liner fame (assuming such leads in any way to > virtue or fame) > > It retains @Peter's preference for a more re-usable roll_die() which > returns a single event, cf the OP's roll() which returns two results). > > > import itertools, random > > def roll_die(): > while True: > yield random.randrange(1, 7) > > def how_many_times(): > return list( itertools.takewhile( lambda r:r[ 0 ] != r[ 1 ], > zip( roll_die(), roll_die() ) > ) > ) > > Also, a claim for 'bonus points' because the one-liner will fit within > 80-characters - if only I didn't have that pernicious and vile habit of > coding a more readable layout. > > It doesn't use a two-arg iter, but still rates because it does use a > relatively-obscure member of the itertools library... >
Nice, but that's only going to give you the ones that don't match. You can then count those, and that's a start, but how do you capture the matching rolls? I smell another opportunity for gratuitous use of a language feature: nonlocal. In a lambda function. Which may require shenanigans of epic proportions. ChrisA -- https://mail.python.org/mailman/listinfo/python-list
