How about this?: python3 -c 'list_ = [1, 3, 5, 4, 2]; am = max((value, index) for index, value in enumerate(list_)); print(am)'
On Wed, Sep 1, 2021 at 6:51 AM ABCCDE921 <atharvasakhala5...@gmail.com> wrote: > Because that does 2 passes over the entire array when you only need one > and there is no option to specify if you want the leftmost or rightmost > element > > > On Wednesday, September 1, 2021 at 12:02:29 PM UTC+5:30, Paul Bryan wrote: > > Why not: > > > > >>> l = [1, 3, 5, 9, 2, 7] > > >>> l.index(max(l)) > > 3 > > >>> l.index(min(l)) > > 0 > > On Tue, 2021-08-31 at 21:25 -0700, ABCCDE921 wrote: > > > I dont want to import numpy > > > > > > argmax(list) > > > returns index of (left most) max element > > > > > > argmin(list) > > > returns index of (left most) min element > -- > https://mail.python.org/mailman/listinfo/python-list > -- https://mail.python.org/mailman/listinfo/python-list
