On 2021-05-12 15:48, Michael F. Stemper wrote: > > On 12/05/2021 08.26, Dino wrote: > > > >> Hi, here's my (probably unusual) problem. Can a Python (3.7+) script > >> access its own source code? > > > > Here is a fairly simple python program that reads itself: > > > > ================================================ > > #!/usr/bin/python > > > > import sys > > > > with open( sys.argv[0], "rt" ) as myself: > > for line in myself: > > junk = sys.stdout.write( "%s" % (line) ) > > > > sys.exit(0) > > ================================================ > > > > It's not bullet-proof. If you put it in a directory in your $PATH and > > run it from somewhere else, it won't work. > > > > Here's a fairly simple option:
========== import inspect import sys print(inspect.getsource(sys.modules[__name__])) ======== -- https://mail.python.org/mailman/listinfo/python-list
