On 2021-02-25 00:42, Davor Levicki wrote:
i have two lists
list1 = ['01:15', 'abc', '01:15', 'def', '01:45', 'ghi' ]
list2 = ['01:15', 'abc', '01:15', 'uvz', '01:45', 'ghi' ]
and when I loop through the list
list_difference = []
for item in list1:
if item not in list2:
list_difference.append(item)
and I managed to get the difference, but I need time as well
because it is a separate item and 'uvz' does not mean to me anything in the
list with a few thousand entries.
I tried to convert it to the dictionary, but it overwrites with last key:value
{'01:15' : 'def'}
If the items belong in pairs, try making the pairs first:
>>> list1 = ['01:15', 'abc', '01:15', 'def', '01:45', 'ghi' ]
>>> list(zip(list1[0 : : 2], list1[1 : : 2]))
[('01:15', 'abc'), ('01:15', 'def'), ('01:45', 'ghi')]
and then work from there.
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