On 2021-02-20 14:40, C W wrote:
Hello everyone,
I'm curious if there is a way take number and back each digit by 3 ?
2342 becomes 9019
8475 becomes 5142
5873 becomes 2540
The tricky part is that 2 becomes 9, not -1.
Here's my toy example and what I attempted,
test_series = pd.Series(list(['2342', '8475', '5873']))
test_series
0 2342
1 8475
2 5873
dtype: object
test_series.str.split('')
[, 2, 3, 4, 2, ]
[, 8, 4, 7, 5, ]
[, 5, 8, 7, 3, ]
dtype: object
What a good approach to this? Is there a method or function that should be
handling this?
Have a look at the 'translate' method of the 'str' class.
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