System environment:
Cent OS 7
Sqlite3 3.34.0 (Compile from source)
Python 3.9.1 (Compile from source)
Django 3.1.5 (Pip install)
1. Compile sqlite3:
./configure --prefix=/home/felix/.local/sqlite/sqlite-3.34.0
make && make install
2. Add sqlite3 lib to lib search path:
export LD_LIBRARY_PATH=/home/felix/.local/sqlite/sqlite-3.34.0/lib
export LD_RUN_PATH=/home/felix/.local/sqlite/sqlite-3.34.0/lib
3. Compile Python 3.9.1
C_INCLUDE_PATH=/home/felix/.local/sqlite/sqlite-3.34.0/include/
CPLUS_INCLUDE_PATH=/home/felix/.local/sqlite/sqlite-3.34.0/include/
LD_RUN_PATH=/home/felix/.local/sqlite/default/lib ./configure
--prefix=/home/felix/.local/python/python-3.9.1 --enable-optimizations
make && make install
4. Test sqlite3
Python 3.9.1 (default, Jan 20 2021, 14:32:50)
[GCC 10.2.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import sqlite3
>>> conn = sqlite3.connect(':memory:')
>>> conn.create_function('f', 2, lambda *args: None, deterministic=True)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
sqlite3.NotSupportedError: deterministic=True requires SQLite 3.8.3 or higher
>>> sqlite3.sqlite_version
'3.34.0'
>>> sqlite3.version
'2.6.0'
>>>
It reports "deterministic=True requires SQLite 3.8.3 or higher", but when
execute sqlite3.sqlite_version it returns 3.34.0 which higher than 3.8.3.
Is there any advice on this issue? thanks.
--
https://mail.python.org/mailman/listinfo/python-list
