On 2021-01-08, Stefan Ram <r...@zedat.fu-berlin.de> wrote:
> Bischoop <bisch...@vimart.net> writes:
>>What I want to learn is if I need get for example four combinations, so
>>how to get in a loop first letter 'a',then another step'a' and again 'a'
>>and 'a', to have 'aaaa' later on'abaa' etc.
>
> I can only guess what you want, maybe something like
>
> word = []
> p = 0
>
> def inc_at( position ):
> word[ position ]= chr( ord( word[ position ])+ 1 )
>
> while True:
> if len( word )< p + 1:
> word =[ "a" ]+ word
> print( "".join( word ))
> p = 0
> o = len( word )- 1 - p
> inc_at( o )
> while p < len( word ) and word[ o ]== '{':
> word[ o ]= "a"
> p += 1
> o -= 1
> if p < len( word ): inc_at( o )
>
> ?
>
>
Yes, it must generate 4 characters long all combination of alphabet,
equivalent to: s = list(''.join(seq) for seq
initertools.product(string.ascii_lowercase, repeat=4)).
I must say that's quite coding you've done.
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