On Fri, 13 Nov 2020 16:04:03 +0000, Stefan Ram wrote: > ChalaoAdda <chalao.a...@gmail.com> writes: >>On Fri, 13 Nov 2020 15:41:20 +0000, Stefan Ram wrote: >>> ChalaoAdda <chalao.a...@gmail.com> writes: >>>>I am trying to read a file from askopenfilename outside the function. >>>>I am getting blank file name. What am I doing wrong? Here is my code. >>>It is possible that you try to read from "pic" before "on_openfile" >>>ever was executed. >>I didn't get you. I click on the menu item "Open" and then from the >>filedialog select a file. And then outside that function I am trying to >>read and print the file. > > I have added two additional statements to your source code: > print( "A" ) and print( "B" ). > > If you now execute this new source code, you might observe that "B" is > being printed before "A" is being printed. > > from tkinter import * > from tkinter import filedialog > > def on_openfile(): > print( "A" ) > global pic pic = filedialog.askopenfilename() > > > root = Tk() > > menubar = Menu(root) > root.config(menu=menubar) > file_menu = Menu(menubar) file_menu.add_command(label="Open", > command=on_openfile) file_menu.add_command(label="Exit", > command=root.destroy) > menubar.add_cascade(label="File", menu=file_menu) > > > print( "B" ) > f = open(pic) > print(f.read()) > > root.mainloop()
Ok. I got the point. So what do I need to do access the variable? How do I return a value from that function? Thanks. -- https://mail.python.org/mailman/listinfo/python-list
