On 01/11/2020 13:38, Bischoop wrote: > On 2020-11-01, Bischoop <bisch...@vimart.net> wrote: >> I'm working on a script i which user inputs letters and then a printed >> words containing those letters. The scripts works however I can't solve >> one problem , it prints also words in which these letters occur more >> than once. >> ------------------- >> Fore example: >> Letters: at >> Output: auto, autobahn. >> ------------------- >> >> I supposed to not print word: "autobahn" because I've given it only one >> letter "a". >> > > Problem's solved. > > ------------ > for word in words: > if all(word.count(x) == letters.count(x) for x in letters): > print(word) > ------------- > > Thanks for suggestions, I didn't had to use counter but going to look > into as it seems useful and interesting. > > Thank You >
But this generates the letters counts for each word. They only need to be generated once (outside the for loop). And using count requires iterating over the letters / words for each x in letters (rather than once). For a large enough collection of words you'd notice the difference. Duncan -- https://mail.python.org/mailman/listinfo/python-list
