Hi,
You can use the trace module for that:
https://docs.python.org/3.8/library/trace.html
Personally I tend to put print statement at strategic places instead, I
find that easier to analyse than a full trace but YMMV.
Maxime
Le dim. 25 oct. 2020 à 01:25, Steve <Gronicus@sga.ninja> a écrit :
> This would seriously help troubleshooting for me. I updated a data file
> and
> now my main program is choking on it. When the program encounters an
> error,
> it dumps a bit of information to the screen for a few steps before the
> error
> but that is not enough.
>
>
>
>
> Footnote:
> English sprakers on a roller coaster: "Weeee"
> Spanish speakers on a rollercoaster: " Nosostros"
>
> -----Original Message-----
> From: Python-list <python-list-bounces+gronicus=sga.ni...@python.org> On
> Behalf Of shrimp_banana
> Sent: Saturday, October 17, 2020 9:47 PM
> To: python-list@python.org
> Subject: Re: File Name issue
>
> On 10/17/20 4:12 PM, Steve wrote:
> > The line:
> > with open("HOURLYLOG.txt", 'r') as infile:
> > works but, when I rename the file, the line:
> > with open("HOURLY-LOG.txt", 'r') as infile:
> > does not. The complaint is: Cannot Assign to operator > > However, I
> have:
> > BPM_O2s=open("BPM-O2-Readings.txt","a")
> > And it works.
> >
> > At first, I thought the issue was due to having the - in the filename.
> >
> > Is there a fix or explanation for this?
> > Steve
>
> I am unsure if this will help but you could try putting an r in front of
> the
> quotes to make it take raw data only.
> ie.
>
> with open(r"HOURLY-LOG.txt", 'r') as infile
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