I am trying to write a simple expression to build a raw string that ends
in a single backslash. My understanding is that a raw string should
ignore attempts at escaping characters but I get this :
>>> a = r'end\'
File "<stdin>", line 1
a = r'end\'
^
SyntaxError: EOL while scanning string literal
I interpret this as meaning that the \' is actually being interpreted as
a literal quote - is that a bug ?
If I try to escaped the backslash I get a different problem:
>>> a = r'end\\'
>>> a
'end\\\\'
>>> print(a)
end\\
>>> len(a)
5
>>> list(a)
['e', 'n', 'd', '\\', '\\']
So you can see that our string (with the escaped backslash) is now 5
characters with two literal backslash characters
The only solution I have found is to do this :
>>> a = r'end' + chr(92)
>>> a
'end\\'
>>> list(a)
['e', 'n', 'd', '\\']
or
>>> a = r'end\\'[:-1]
>>> list(a)
['e', 'n', 'd', '\\']
Neither of which are nice.
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