On 23/09/20 7:16 am, Yakov Shalunov wrote:
l0, l1 = ([x for x in l if cond(x) else x]) l0, l1, l2 = ([x for x in l if cond0(x) else x**2 if cond1(x) else x**3])
This syntax seems a bit convoluted. One of the result expressions is at the beginning as usual, but the rest are tacked on the end. And it's far from obvious that it returns multiple lists instead of a single list with alternative values, as you would get from [(x if cond0(x) else x**2 if cond1(x) else x**3) for x in l] which at first glance seems very similar. Also I'm not sure how this would interact with the existing comprehension syntax in its full generality, where you can have multiple "for" and "if" clauses mixed in any order.
A possible alternative would be a partition library function in the same vein as `map` and `filter`
That sounds like a much better idea for something that is so rarely needed. Although it probably wouldn't be as fast as an LC could potentially be, due to the need to call a user-supplied function for every item. -- Greg -- https://mail.python.org/mailman/listinfo/python-list
