2qdxy4rzwzuui...@potatochowder.com wrote: > On 2020-08-26 at 14:22:10 +0100, > Chris Green <c...@isbd.net> wrote: > > > I have the following line in Python 2:- > > > > msgstr = string.join(popmsg[1], "\n") # popmsg[1] is a list containing > the lines of the message > > > > ... so I changed it to:- > > > > s = "\n" > > msgstr = s.join(popmsg[1]) # popmsg[1] is a list containing the > > lines of the message > > > > However this still doesn't work because popmsg[1] isn't a list of > > strings, I get the error:- > > > > TypeError: sequence item 0: expected str instance, bytes found > > > > So how do I do this? I can see clumsy ways by a loop working through > > the list in popmsg[1] but surely there must be a way that's as neat > > and elegant as the Python 2 way was? > > Join bytes objects with a byte object: > > b"\n".join(popmsg[1])
Aaahhh! Thank you (and the other reply). -- Chris Green ยท -- https://mail.python.org/mailman/listinfo/python-list
