On 26/08/2020 19:58, Joel Goldstick wrote:
On Wed, Aug 26, 2020 at 3:43 AM ADITYA <gautam.goari...@gmail.com> wrote:
Dear Sir/Ma’am
I am requesting you to satisfy me about float number in Range function,
because in the argument of range we can take integer but not double or
float whenever double as well as float are integer in nature but when we
use double/float in, it gives error that- “'float' object cannot be
interpreted as an integer.” If we want to increment the number by half or
quarter what can I do.
For ex- Range(1,3,0.5) I want it gives Output as [1 1.5 2 2.5 3)
Take a look at this:
l = [i/2 for i in range(2,7)]
l
[1.0, 1.5, 2.0, 2.5, 3.0]
This is a neat solution! To make it more user-friendly, the above needs
to be wrapped in a convenience function that the user can call using
arguments like "(1,3,0.5)" and not have to think about the 'multiplies'
and 'divides'.
The problem with constructing such a list is that it is 'expensive', ie
if the range is large, more storage-space will be required. In the same
way that range() moved to a storage-averse model in Python3, herewith a
pair of generator solutions - it might be quite fun to compare the
performances (PSL's time library).
My first thought was that the count() from the itertools library enables
one to step using a floating-point number. So, herewith two
generator-based solutions:-
<<< Code NB Python v3.8 >>>
def fp_range( start:float, stop:float, step:float=1.0 )->float:
"""Generate a range of floating-point numbers."""
if stop <= start:
raise OverflowError( "RangeError: start must be less than stop" )
x = start
while x < stop:
yield x
x += step
try:
for fp_number in fp_range( 1, 3, 0.5 ):
print( fp_number )
except OverflowError as e:
print( e )
print( "*"*12 )
try:
for fp_number in fp_range( 1, 3, 0.25 ):
print( fp_number )
except OverflowError as e:
print( e )
print( "+"*12 )
import itertools
def fp_iter( start:float, stop:float, step:float=1.0 )->float:
"""Generate a range of floating-point numbers using
itertools.count()."""
if stop <= start:
raise OverflowError( "RangeError: start must be less than stop" )
for x in itertools.count( start, step ):
if x >= stop:
break
yield x
for fp_number in fp_iter( 1, 3, 0.5 ):
print( fp_number )
print( "*"*12 )
for fp_number in fp_iter( 1, 3, 0.25 ):
print( fp_number )
print( "*"*12 )
try:
for fp_number in fp_iter( 3, 1, 0.5 ):
print( fp_number )
except OverflowError as e:
print( e )
<<< Console.out >>>
1
1.5
2.0
2.5
************
1
1.25
1.5
1.75
2.0
2.25
2.5
2.75
++++++++++++
1
1.5
2.0
2.5
************
1
1.25
1.5
1.75
2.0
2.25
2.5
2.75
************
RangeError: start must be less than stop
--
Regards =dn
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