A better way would be to just do
nestedl = [[2], [], [], [l, b, n]] #nested list
for a in nestedl: #taking all the sublist
for b in a: #iterating through the sub
print(b)
Though it is easy the only limitation is that it works only if the elements are
lists. Which we can be easily overcome by using an if statement to check the
elements type.
On Fri, 6 Mar, 2020, 6:30 pm , <sinnd...@gmail.com> wrote:
> Hi All,
> I am new to python.
> I have a irregular nested lists in a list.
> Please help me to iterate through each element.
>
> Thanks much in advance.
>
> Sample Ex
>
> aList = [[2,'jkj'],[],[],['kite',88,'ooo','pop','push','pull'],['hello']]
>
> expected output:
> 2,jkj,,,kite,88,ooo,pop,push,pull,hello
>
> --
> https://mail.python.org/mailman/listinfo/python-list
>
On Fri, 6 Mar, 2020, 6:30 pm , <sinnd...@gmail.com> wrote:
> Hi All,
> I am new to python.
> I have a irregular nested lists in a list.
> Please help me to iterate through each element.
>
> Thanks much in advance.
>
> Sample Ex
>
> aList = [[2,'jkj'],[],[],['kite',88,'ooo','pop','push','pull'],['hello']]
>
> expected output:
> 2,jkj,,,kite,88,ooo,pop,push,pull,hello
>
> --
> https://mail.python.org/mailman/listinfo/python-list
>
--
https://mail.python.org/mailman/listinfo/python-list
