Madhavan Bomidi <blmadha...@gmail.com> writes:
> I have the following IDL program lines. I want to write equivalent
> Python program lines. Can anyone suggest me equivalent Pythons program
> lines?
>
> # ------------------- 1 ----------------------- #
> How to handle the format in IDL to Python?
>
> IDL program line:
>
> print,'Column ',J,' of product matrix A*AINV:',format='(1X,A7,I3,A27)'
>
>
> Python program line written by me:
>
> print('Column '+str(j)+' of product matrix A*AINV:')
You could just use
print('Column', j, 'of product matrix A*AINV:')
but if you need to copy the I3 format:
print('Column {0:3} of product matrix A*AINV:'.format(j))
I don't know what the 1X format does. The A7 and A27 formats just seem
to involve the programmer counting the strings. Very odd.
> #-------------------2 ------------------------ #
> How the JMP can be transformed in Python?
>
> IDL program lines:
>
> FOR K=1,M DO BEGIN
> FOR I=1,M DO BEGIN
> IF I NE K THEN BEGIN
> IF WK(K-1,K-1) EQ 0 THEN BEGIN
> L=1
> JMP: IF WK(L-1,K-1) EQ 0 THEN BEGIN
> L=L+1
> GOTO, JMP
> ENDIF
> FOR J=K,2*M DO BEGIN
> WK(K-1,J-1)=WK(K-1,J-1)+WK(L-1,J-1)
> ENDFOR
> ENDIF
> U=-WK(I-1,K-1)/WK(K-1,K-1)
> FOR J=K+1,2*M DO BEGIN
> WK(I-1,J-1)=WK(I-1,J-1)+U*WK(K-1,J-1)
> ENDFOR
> ENDIF
> ENDFOR
> ENDFOR
>
> JMP: RETURN
This is very odd. What does it mean when a label is duplicated in IDL?
If the second one were not there, this:
JMP: IF WK(L-1,K-1) EQ 0 THEN BEGIN
L=L+1
GOTO, JMP
ENDIF
would just be a while loop:
while WK[L-1,K-1] == 0:
L=L+1
<cut>
By the way, all those -1s suggest that the IDL was itself a translation
from a language with 1-based array indexing. All that might be able to
be tidied up.
--
Ben.
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