Ulrich Goebel <m...@fam-goebel.de> writes:
> Hi,
>
> I have to call commands from inside a python skript. These commands are
> in fact other python scripts. So I made
>
> os.system('\.Test.py')
>
> That works.
In a string \. is the same as . So this should execute the command '.Test.py'.
Is that really what you did? Or did you mean os.system('./Test.py') which is
much more probable.
NOTE: Never retype the commands that you used, but copy and paste them.
>
> Now I tried to use
>
> supprocess.call(['.\', 'test.py'])
>
That can't have given the error below, as it would have to be subprocess.call,
not supprocess.call.
And then also '.\' would have given a syntax error.
NOTE: Never retype the commands that you used, but copy and paste them.
> That doesn't work but ends in an error:
>
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> File "/usr/lib/python3.5/subprocess.py", line 557, in call
> with Popen(*popenargs, **kwargs) as p:
> File "/usr/lib/python3.5/subprocess.py", line 947, in __init__
> restore_signals, start_new_session)
> File "/usr/lib/python3.5/subprocess.py", line 1551, in _execute_child
> raise child_exception_type(errno_num, err_msg)
> PermissionError: [Errno 13] Permission denied
>
> Using
>
> subprocess.call(['./', 'Test.py'], shell=True)
>
> I get
>
> Test.py: 1: Test.py: ./: Permission denied
>
Why would you do that, splitting './Test.py' in two parts? That doesn't work.
> Is there a simple way to use subprocess in this usecase?
>
subprocess.call(['./Test.py'])
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Pieter van Oostrum
www: http://pieter.vanoostrum.org/
PGP key: [8DAE142BE17999C4]
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