On 14 Nov 2019, at 14:06, R.Wieser wrote:

I've also tried moving "MyVar = 7" to the first line, but that doesn't
change anything.  Using "global MyVar" works..

Try

def outer():
        MyVar = 10
        def Proc1():
                nonlocal MyVar
                MyVar = 5
        Proc1()
        
MyVar = 7
outer()
print(MyVar)

From the documentation

The nonlocal statement causes the listed identifiers to refer to previously bound variables in the nearest ******enclosing scope excluding globals******. This is important because the default behavior for binding is to search the local namespace first. The statement allows encapsulated code to rebind variables outside of the local scope besides the global (module) scope.

Names listed in a nonlocal statement, unlike those listed in a global statement, must refer to pre-existing bindings in an enclosing scope (the scope in which a new binding should be created cannot be determined unambiguously).

Names listed in a nonlocal statement must not collide with pre-existing bindings in the local scope.
--
https://mail.python.org/mailman/listinfo/python-list

Reply via email to