> I expected this to return 3 but it only returned 1.
>
> matrix1 = [[1, -2], [-3, 4],]
> matrix2 = [[2, -1], [0, -1]]
> matrix3 = [[2, -1], [0, -1]]
>
> def add(*matrix):
> print(len(locals()))
>
> print(add(matrix1, matrix2))
In this case, locals will be a dictionary with exactly one key. The key
will be "matrix", and its value will be a tuple of the two matrices
matrix1 and matrix2. One solution (the wrong solution) to your problem
would be to instead have
# Don't do this --- this is to illustrate what locals is doing
def add(*matrix):
print(len(locals()['matrix']))
Now let's get to the right way to do this. Python stores the arguments
specified by *matrix as a tuple of the name `matrix`. Of course, this is
what locals what telling us, but there is no need to go through locals.
Instead, you can do
def add(*matrix):
print(len(matrix))
and this will tell you how many arguments were passed in.
Good luck!
David Lowry-Duda
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