jf...@ms4.hinet.net wrote:
> I had tried the following script test.py:
> --------
> import tkinter as tk
>
> class Demo(tk.Frame):
> def __init__(self):
> tk.Frame.__init__(self, name='demo')
> self.pack()
>
> panel = tk.Frame(self, name='panel')
> panel.pack()
>
> start = tk.Button(text='Start', name='start')
> start.grid(in_=panel)
>
> btn = self.nametowidget('panel.start')
> btn.config(state='disabled')
>
> Demo().mainloop()
> --------
>
> It fails on nametowidget() function. My intention is to use 'in_' to
> change the parent of 'start' widget from the default Tk object to 'panel',
> but failed with KeyError: 'start'.
>
> below is part of the snapshot in pdb,
> ...
>> d:\works\python\test.py(11)__init__()
> -> start = tk.Button(text='Start', name='start')
> (Pdb) !panel.winfo_parent()
> '.demo'
> (Pdb) next
>> d:\works\python\test.py(12)__init__()
> -> start.grid(in_=panel)
> (Pdb) !start.winfo_parent()
> '.'
> (Pdb) next
>> d:\works\python\test.py(14)__init__()
> -> btn = self.nametowidget('panel.start')
> (Pdb) !start.winfo_parent()
> '.'
>
> --Jach
I think that the `in_` argument is used correctly. It's just that your
expectation that the name is changed to reflect the layout hierarchy is
wrong.
To manipulate the start button you can use the `start` variable directly:
start.config(state='disabled')
To find all slaves of the panel use
panel.grid_slaves()
$ cat grid_in.py
import tkinter as tk
class Demo(tk.Frame):
def __init__(self):
tk.Frame.__init__(self, name='demo')
self.pack()
self.panel = panel = tk.Frame(self, name='panel')
panel.pack()
start = tk.Button(text='Start', name='start')
start.grid(in_=panel)
for btn in panel.grid_slaves():
print("disabling", btn._w)
btn.config(state='disabled')
Demo() #.mainloop()
$ python3 grid_in.py
disabling .start
$
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