MRAB <pyt...@mrabarnett.plus.com> writes:
> On 2019-05-23 22:55, Cecil Westerhof wrote:
>> Cecil Westerhof <ce...@decebal.nl> writes:
>>
>>> I am using Twython to post updates on Twitter. Lately there is now and
>>> then a problem with my internet connection. I am using:
>>> posted = twitter.update_status(status = message,
>>> in_reply_to_status_id = message_id,
>>> trim_user = True)
>>>
>>> What would be the best way to catch a connection error and try it (for
>>> example) again maximum three times with a delay of one minute?
>>
>> At the moment I solved it with the following:
>> max_tries = 3
>> current_try = 1
>> while True:
>> try:
>> posted = twitter.update_status(status = message,
>> in_reply_to_status_id =
>> message_id,
>> trim_user = True)
>> return posted['id']
>> except TwythonError as e:
>> print('Failed on try: {0}'.format(current_try))
>> if not 'Temporary failure in name resolution' in e.msg:
>> raise
>> if current_try == max_tries:
>> raise
>> current_try += 1
>> time.sleep(60)
>>
>> Is this a good way to do it, or can it be improved on?
>>
>> When it goes OK I just return from the function.
>> If it goes wrong for something else as failure in the name resolution
>> I re-raise the exception.
>> When the maximum tries are done I re-raise the exception.
>> Otherwise I wait a minute to try it again.
>>
> You have a 'while' loop with a counter; you can replace that with a
> 'for' loop.
I did not do that consciously, because I have to try until it is
successful an I return, or I reached the max tries and re-raise the
exception. With a for loop I could exit the loop and cannot re-raise
the exception.
--
Cecil Westerhof
Senior Software Engineer
LinkedIn: http://www.linkedin.com/in/cecilwesterhof
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