In comp.lang.python, Paul Rubin <no.email@nospam.invalid> wrote:
> Eli the Bearded <*@eli.users.panix.com> writes:
>> # decode a single hex digit
>> def hord(c): ...
>
> def hord(c): return int(c, 16)
That's a good method, thanks.
> > # decode quoted printable, specifically the MIME-encoded words
> > # variant which is slightly different than the body text variant
> > def decodeqp(v): ...
>
> I think this is supposed to mean:
>
> from itertools import islice
>
> def getbytes(v):
> cs = iter(bytes(v,'ascii'))
> for c in cs:
> if c == ord('='):
> h1,h2 = islice(cs,2)
> yield int(chr(h1)+chr(h2), 16)
> else: yield c
>
> def decodeqp(v):
> return bytes(getbytes(v))
>
> print (decodeqp('=21_yes')) # prints "b'!_yes'"
But that's not the output my sample produced.
def getbytes(v):
cs = iter(bytes(v,'ascii'))
for c in cs:
if c == ord('='):
h1,h2 = islice(cs,2)
yield int(chr(h1)+chr(h2), 16)
elif c == ord('_'):
yield ord(' ')
else: yield c
That's certainly a lot cleaner that what I had.
Elijah
------
and shorter than the one in /usr/lib/python3.5/quopri.py
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