On 2019-04-23 10:56, Vincent Vande Vyvre wrote:
Hi,
In a CPython lib I have an _init() method wich take one argument, a file
name.
char *fname;
if (!PyArg_ParseTuple(args, "s", &fname))
return NULL;
So, if I instanciate my object with a bad argument I've a good error
message:
tif = ImgProc(123)
TypeError: argument 1 must be str, not int
(followed by the traceback)
But if I do:
try:
tif = ImgProc(123)
except Exception as why:
print("Error:", why)
I get just:
Error: <class '_liboqapy.ImgProc'> returned a result with an error set
Without traceback. That's not very usefull.
I prefer to keep the instanciation of this object into a try-except bloc
but how to read the error message ?
Have a look ta the 'traceback' module.
Example:
import traceback
try:
1/0
except Exception as ex:
print('Error:', ex)
traceback.print_exc()
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