On Fri, Apr 5, 2019 at 5:56 PM Sayth Renshaw <flebber.c...@gmail.com> wrote:
>
> I saw this fizzbuzz in Eloquent Javascript and thought its really nice. Not
> all the usual if else version, just if.
>
> for (let n = 1; n <= 100; n++) {
> let output = "";
> if (n % 3 == 0) output += "Fizz";
> if (n % 5 == 0) output += "Buzz";
> console.log(output || n);
> }
>
> I can't quite get a nice version like this out.
>
> This was my attempt to mimick it. I am sure Python can get it cleaner, but I
> had never thought about not doing if else for Fizzbuzz its just the way I did
> it.
>
> n = range(100)
> output = ""
> for num in n:
> if (num % 3 == 0): output += "Fizz"
> if (num % 5 == 0): output += "Buzz"
> print(output or num)
>
> Haven't quite got it. But is possible nice and succinct like the javascript
> version. Maybe lambda will do it, gonna try that.
I'd recommend a more direct transformation, specifically resetting
'output' inside the loop. Otherwise, you basically have the same code.
> Any unique mindlowing style FizzBuzz I would never have considered and can
> learn off?
>
print(*[[n,"Fizz","Buzz","Fizzbuzz"][int("300102100120100"[n%15])] for
n in range(1,101)], sep="\n")
This is not good code, and if anyone asks, I didn't say you were
allowed to do this in an interview.
ChrisA
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