On Tue, Mar 26, 2019 at 5:08 AM Bassam Abdul-Baki <babdulb...@gmail.com> wrote:
>
> def per(n, steps = 0):
> if len(str(result)) == 1:
> print(" --- DONE ---")
> return "DONE"
> else:
> per(result, steps)
>
> ----------
>
> What the program does:
> If I run per(X) and X is a multiple of 10, I should end up with 0 in a
> finite amount of steps.
>
> The problem:
> If I run per(54), I do not get 'DONE' printed through the return
> statement. WRONG!
>
> If I run per(20), I do get 'DONE' printed through the return statement.
> CORRECT!
>
> 20, 30, etc. are correct. 25, 45, etc. are not.
>
> Is this a bug?
Yes, it is - not a bug in Python, but a bug in the above code :)
I would recommend exploring the part of the code that I quoted above,
and researching how recursion works, and specifically what 'return'
does. That should put you on the right path to figuring this out.
ChrisA
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