Without using regular expressions, if you just want to extract the word
"int" or "float" you can substring the results by converting what type says
to a string:
>>> a = 5
>>> str(type(a))[8:11]
'int'
>>> a=5.0
>>> str(type(a))[8:13]
'float'
Since the format and length vary, this may not meet your needs. You could
search for the first index where there is a single quote and then the next
and take what is in between.
You can run this in-line or make a function that might work for at least the
basic types:
>>> a = 5
>>> text = str(type(a))
>>> first = text.find("'")
>>> first += 1
>>> second = text.find("'", first)
>>> first, second
(8, 11)
>>> text[first : second]
'int'
>>> print(text[first : second])
Int
If I do the same with a float like 5.0:
>>> a=5.0
>>> text = str(type(a))
>>> first = text.find("'")
>>> first += 1
>>> second = text.find("'", first)
>>> print(text[first : second])
float
For a list:
>>> a = ["list", "of", "anything"]
...
>>> print(text[first : second])
list
Of course this is so simple it must be out there in some module.
-----Original Message-----
From: Python-list <python-list-bounces+avigross=verizon....@python.org> On
Behalf Of ^Bart
Sent: Sunday, February 10, 2019 4:43 PM
To: python-list@python.org
Subject: The use of type()
I need to print something like "this variable is int" or "this variable is
string"
n1 = 10
n2 = 23
print ("Total of n1+n2 is: ",n1+n2," the type is", type(n1+n2))
When I run it I have:
Total of n1+n2 is: 33 the type is <class 'int'> >>>
I'd like to read "the type is int" and NOT "the type is <class 'int'>, how
could I solve it?
^Bart
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