On Thursday, February 7, 2019 at 11:45:23 PM UTC-7, Kaka wrote:
> for i in range(len(A.hp)):
>
> for j in range(len(run_parameters.bits_Mod)):
> req_slots[j] = math.ceil((A.T[i])
>
> for g in Temp[i]["Available_ranges"][j]:
> for s in range(g[0], g[-1]):
> if (s+req_slots[j]-1) <= g[-1]:
> if (Temp[i]['cost'][j] <= (run_parameters.PSD): ------ When
> this condition is true i want to break the nested loop and start from the
> begining
> served_count +=1
> A.T[i]["First_index"]= s
> A.T[i]["Last_index"]= s+req_slots[j]-1
> A.T[i]["Status"]= 1
> A.T[i]["Selected_MOD"] = j
> break
>
> I have this code. When the last "if" condition is satisfied, i want to break
> all the loops and start the nested loop for next i. else, the loop should
> continue.
>
> can anyone help me?
In addition to the two methods Peter posted there is also
the obvious way of using a flag (but perhaps this is what
you were trying to avoid?)
for i in (1,2,3):
nexti = False
for g in (1,2,3):
for s in (1,2,3):
print (i,g,s)
if (g,s) == (2,2):
nexti = True
break
if nexti: break
You can also use exceptions to do a multi-level break:
class Next_i (Exception): pass
for i in (1,2,3):
try:
for g in (1,2,3):
for s in (1,2,3):
print (i,g,s)
if (g,s) == (2,2):
raise Next_i
except Next_i: continue
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