I may be missing something, but the focus seems to be only on the rightmost
digit. You can get that with
str(day)[-1]
or with
day % 10
Problem: print 1..31 using suffixes such as 1st, 2nd, 3rd, 4th ...
So your dictionary needs entries for "1" or 1 and "2" or "2" and of course 3
becoming 3rd.
And, frankly, you don't even need a dictionary as a one-liner will do.
Here is an example using a helper function:
""" Use last digit to determine suffix """
def nthSuffix(day):
nth = day % 10
suffix = "st" if nth == 1 else ("nd" if nth == 2 else ("rd" if nth == 3
else "th"))
return str(day) + suffix
Output:
>>> for day in range(1, 32):
print( nthSuffix(day))
1st
2nd
3rd
4th
5th
6th
7th
8th
9th
10th
11st
12nd
13rd
14th
15th
16th
17th
18th
19th
20th
21st
22nd
23rd
24th
25th
26th
27th
28th
29th
30th
31st
-----Original Message-----
From: Python-list <python-list-bounces+avigross=verizon....@python.org> On
Behalf Of Sayth Renshaw
Sent: Saturday, February 2, 2019 8:53 PM
To: python-list@python.org
Subject: Re: Implement C's Switch in Python 3
> >I am trying to convert a switch statement from C into Python. (why?
> >practising).
> >
> >This is the C code.
> >
> >printf("Dated this %d", day);
> > switch (day) {
> > case 1: case 21: case 31:
> > printf("st"); break;
> > case 2: case 22:
> > printf("nd"); break;
> > case 3: case 23:
> > printf("rd"); break;
> > default: printf("th"); break;
> >
> > }
> > printf(" day of ");
> >
> >#Premise if the use enter an int as the date 21 for example it would
print 21st. It appends the correct suffix onto a date.
> >Reading and trying to implement a function that uses a dictionary.
> >Not sure how to supply list into it to keep it brief and with default
> >case of 'th'.
> >
> >This is my current code.
> >
> >def f(x):
> > return {
> > [1, 21, 31]: "st",
> > [2, 22]: "nd",
> > [3, 23]: "rd",
> > }.get(x, "th")
> >
> >
> >print(f(21))
> >
> >I have an unhashable type list. Whats the best way to go?
>
> Skip has commented on lists being unhashable. We can elaborate on that
> if you like.
>
> However, even if you went to tuples (which would let you construct the
> dict you lay out above), there is another problem.
>
> You're looking up "x" in the dict. But the keys of the dict are not
> integers, they are lists (or tuples) or integers, so they won't match.
>
> You _could_ do this:
>
> return {
> 1: "st", 21: "st", 31: "st",
> 2: "nd", 22: "nd",
> 3: "rd", 23: "rd",
> }.get(x, "th")
>
> which makes distinct entries for each integer value of interest.
>
> The conventional approach would normally be:
>
> if x in (1, 21, 31):
> return "st"
> if x in (2, 22):
> return "nd"
> if x in (3, 23):
> return "rd"
> return "th"
>
> While this works for a small number of choices, if you had a huge dict
> with lots of possible values you could return to your
> dict-keyed-on-tuples approach. You would need to try each tuple in turn:
>
> mapping = {
> (1, 21, 31): "st",
> (2, 22): "nd",
> (3, 23): "rd",
> }
> for key, suffix in mapping.items():
> if x in key:
> return suffix
> return "th"
>
> However, for big dictionaries (with many keys) you loose a key
> strength of dicts: constant time lookup. You can see the above code
> (and the earlier "if" code) are rather linear, with run time going up
> linearly with the number of keys. You're better with the int->string
> single value dict version.
>
> Cheers,
> Cameron Simpson
It seems odd with C having switch that its cleaner and more efficient than
python where we are having to implement our own functions to recreate switch
everytime.
Or perhaps use a 3rd party library like
https://github.com/mikeckennedy/python-switch
You have both given good options, it seems there are no standard approaches
in this case.
Cheers
Sayth
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