On Sun, 27 Jan 2019 15:59:42 +0100, ^Bart wrote:
>> You have got to a starting point - you have three numbers. Good.
>>
>> Where do you do go from here?
>>
>> I would start with two of the numbers, and work out which one is
>> higher.
>
> # SOLVED!!!
> number1 = int( input("Insert the first number: "))
>
> number2 = int( input("Insert the second number: "))
>
> number3 = int( input("Insert the third number: "))
>
> numbermax = number1
>
> numbermiddle = number2
>
> numbermin = number3
>
> if number2 > number1 and number2 > number3:
> numbermax = number2
>
> print("Number max is: ",numbermax)
>
> if number1 > number2 and number1 > number3:
> numbermax = number1
>
> print("Number max is: ",numbermax)
>
> if number3 > number2 and number3 > number1:
> numbermax = number3
>
> print("Number max is: ",numbermax)
>
> if number2 < number1 and number2 < number3:
> numbermin = number2
>
> print("Number min is: ",numbermin)
>
> if number1 < number2 and number1 < number3:
> numbermin = number1
>
> print("Number min is: ",numbermin)
>
> if number3 < number2 and number3 < number1:
> numbermin = number3
>
> print("Number min is: ",numbermin)
>
> numbermiddle = (number1+number2+number3)-(numbermax+numbermin)
>
> print("Number middle is: ",numbermiddle)
>
> Maybe it's not the best way to do it but at this time in our course we
> should try to solve problems just by using few things like if, else,
> etc. I know there's also min or max but before to use them we must
> understand if else! :)
>
>> Frank Millman
>
> Thank you very much, you helped me to power on my brain! :D ^Bart
as a follow on exercise if you have covered them yet, convert your code
into a function takes the 3 numbers as parameters. you will find as you
progress it is a better way of structuring your program & increases
flexibility.
good luck with your learning & congratulations on asking for assistance
not simply a solution
--
Zoidberg: Muy macho. Hey, gringos, here comes El Zoido to ruin
your drinking water!
--
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