Reinhold Birkenfeld wrote: > > x = [ yield r for r in iterable ] > > Which is quite different from > > x = (yield) in iterable > > which is currently (PEP 342) equivalent to > > _ = (yield) > x = _ in iterable > > So, no further tinkering with yield, I'm afraid. > > Reinhold
Is the statement yield from iterable also in danger to be ambigous? The resolution of "(yield) from iterable" into _ = (yield) x = _ from iterable would not result in valid Python syntax. Kay -- http://mail.python.org/mailman/listinfo/python-list
