On Fri, Sep 14, 2018 at 2:37 PM, Noel P. CUA <np...@donbosco.edu.ph> wrote:
> compose your own octave script to calculate the machine
> epsilon. Analyze the code.
>
> epsilon = 1
> DO
> IF (epsilon+1<=1) EXIT
> epsilon = epsilon/2
> END DO
> epsilon = 2 x epsilon
>
epsilon = 1
while epsilon + 1 > 1:
epsilon = epsilon / 2.0
epsilon = 2 * epsilon
This will not work in Octave. But maybe it will help you in improving
your understanding of the solution.
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