On Sat, 1 Sep 2018 10:11:59 -0700 (PDT), moha...@gmail.com wrote:
> All,
>
> I m trying to run this small script to find the lowest of the given
> array of numbers. The script works fine for various combination of
> inputs but fails in a weird way for a particular set of inputs, can
> anyone point the mistake in the script and the behavior.
>
> Script
>
> x = input ("Enter the numbers separated by space and press ENTER :")
> x = x.split(" ")
>
> def checkmin(arr):
> lowest = arr[0]
> for count in range(0,len(arr),1):
> if arr[count] < lowest :
> lowest = arr[count]
> else :
> pass
> print (lowest)
> return lowest
>
> minimum = checkmin(x)
> print ("Lowest : {0}".format (minimum))
>
>
> Weird output is as below.
>
>================== RESTART: C:\Users\mohan\Desktop\temp.py ==================
> Enter the numbers separated by space and press ENTER :5 90 63 82 59 24
> 5
> 5
> 5
> 5
> 5
> 24
> Lowest : 24
Assuming this is homework, here's a hint:
Instead of "5 90 63 82 59 24", feed it "2 1111", or "1 099999"
or "1 2 3 ." (yes, ".").
As a stylistic matter, looping over an array's indices is more
cumbersome than looping over the elements of the array ("for x in arr:"),
unless you actually need the index for something, which you don't.
Also, two of the three arguments you pass to range can be omitted.
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