-----Original Message----- From: Python-list <python-list- bounces+jcasale=activenetwerx....@python.org> On Behalf Of Skip Montanaro Sent: Wednesday, August 15, 2018 3:26 PM To: Python <python-list@python.org> Subject: lxml namespace as an attribute > Much of XML makes no sense to me. Namespaces are one thing. If I'm > parsing a document where namespaces are defined at the top level, then > adding namespaces=root.nsmap works when calling the xpath method. I > more-or-less get that. > > What I don't understand is how I'm supposed to search for a tag when > the namespace appears to be defined as an attribute of the tag itself. > I have some SOAP XML I'm trying to parse. It looks roughly like this: > > <s: Envelope xmlns:a="..." xmlns:s="..."> > <s:Header> > ... > </s:Header> > <s:Body> > <Tag xmlns="http://some/new/path";> > ... > </Tag> > </s:Body> > > If the document is "doc", I can find the body like so: > > body = doc.xpath(".//Body" namespaces=doc.nsmap) > > I don't understand how to find Tag, however. When I iterate over the > body's children, printing them out, I see that Tag's name is actually: > > {http://some/new/path}Tag > > yet that namespace is unknown to me until I find Tag. It seems I'm > stuck in a chicken-and-egg situation. Without knowing that > http://some/new/path namespace, is there a way to cleanly find all > instances of Tag?
See https://lxml.de/tutorial.html#namespaces and https://lxml.de/2.1/FAQ.html#how-can-i-specify-a-default-namespace-for-xpath-expressions for direction. I don't have Python at my current location but I trust that will point you straight. jlc -- https://mail.python.org/mailman/listinfo/python-list
