https://docs.python.org/3.7/library/constants.html
"None The sole value of the type NoneType..." "x is None" and "type(x) is type(None)" are equivalent because of that. I think though that the better way to do the first tests would be to use isinstance https://docs.python.org/3.7/library/functions.html#isinstance isinstance({}, dict) isinstance(3, int) And I suppose if you really wanted: isinstance(None, type(None)) -----Original Message----- From: Python-list [mailto:python-list-bounces+david.raymond=tomtom....@python.org] On Behalf Of Tobiah Sent: Tuesday, July 24, 2018 3:33 PM To: python-list@python.org Subject: Checking whether type is None Consider: >>> type({}) is dict True >>> type(3) is int True >>> type(None) is None False Obvious I guess, since the type object is not None. So what would I compare type(None) to? >>> type(None) <type 'NoneType'> >>> type(None) is NoneType Traceback (most recent call last): File "<stdin>", line 1, in <module> NameError: name 'NoneType' is not defined I know I ask whether: >>> thing is None but I wanted a generic test. I'm trying to get away from things like: >>> type(thing) is type(None) because of something I read somewhere preferring my original test method. Thanks -- https://mail.python.org/mailman/listinfo/python-list -- https://mail.python.org/mailman/listinfo/python-list
