Kuljo wrote:
> Kuljo wrote:
>>I'm so sorry to bore you with this trivial problem. Allthou: I have string
>>having 0x0a as new line, but I should have \n instead.
> I have found this in the meantime:
>>>>nl="\\"+"n"
Note: this is unnecessary. You could just do nl='\\n' instead, and you
don't need the variable "nl" either, which by the way is confusingly
named. Your variable "nl" is actually bound to the two character
sequence \ followed by n instead of a "newline". Is that really what
you wanted?
>>>>text_new=replace(text_old, chr(10), nl)
This use of replace() is deprecated. Use text_old.replace() instead.
> It works.
For some definitions of "works". This only works if you wanted the
*single* character represented by '\x0a' to turn into the *two*
characters backslash-followed-by-letter-n. The following you might find
instructive:
>>> old = 'some\x0atext'
>>> old
'some\ntext'
>>> print old
some
text
>>> old.encode('string-escape')
'some\\ntext'
>>> print old.encode('string-escape')
some\ntext
This will turn other control characters into their equivalent
two-character escaped representation as well, such as \t and \r, as
necessary.
-Peter
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