05.05.18 12:59, Steven D'Aprano пише:
On Sat, 05 May 2018 10:31:17 +0300, Serhiy Storchaka wrote:
Consider a concrete example. You need to sort a list of 2- or 3- element
tuples by the first and third items (third items are strings if
presented). itemgetter(0, 2) doesn't work because some tuples has only 2
items. But you can use the following lambdas:
lambda t: t[0:3:2]
should also work.
Right, this works in this special case (for tuples and 2-items key). You
can even utilize itemgetter()!
itemgetter(slice(0, 3, 2))
lambda t: (t[0], t[2] if len(t) > 2 else '')
lambda t: (t[0], t[2]) if len(t) > 2 else (t[0],)
lambda t: (t[0], (t + ('',))[2])
lambda t: t[:1] + t[2:]
So which of these is the "One Obvious Way"?
Depending on the details of the problem and the background of the
author, the first or the second options can be the most obvious way. Or
any other.
The second and the forth options support also the case when there is no
natural minimal value for third items (e.g. for negative integers) or if
you want to order 2-tuples before 3-tuples with empty third item and the
same first item. This isn't possible with itemgetter with default
arguments.
Nobody suggests that itemgetter is a magic wand that ought to solve every
imaginable problem. There will always be sufficiently complex examples
where you have to write your own key function.
Right. And it looks to me, that the case in which you want to use
itemgetter with default arguments is the case where you have to write
your own key function.
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