Seb wrote:
I was wondering is whether there's a faster way of multiplying each row (1x3) of a matrix by another matrix (3x3), compared to looping through the matrix row by row as shown in the code.
Just multiply the two matrices together. If A is an nx3 matrix and B is a 3x3 matrix, then C = A @ B is an nx3 matrix where C[i] = A[i] @ B. (This is a property of matrix multiplication in general, nothing special about numpy.) -- Greg -- https://mail.python.org/mailman/listinfo/python-list
