On Sun, Feb 25, 2018 at 8:05 PM, INADA Naoki <songofaca...@gmail.com> wrote: > https://docs.python.org/3.6/library/itertools.html#itertools.product
I don't see how you would use itertools.product to do what the OP asked for. You could use itertools.chain.from_iterable, though: py> names = ['Jack', 'Susan'] py> list(chain.from_iterable(names)) ['J', 'a', 'c', 'k', 'S', 'u', 's', 'a', 'n'] -- https://mail.python.org/mailman/listinfo/python-list
