On Mon, Feb 12, 2018 at 9:40 AM, lampahome <pahome.c...@mirlab.org> wrote:
> I want to know abspath of python script followed by steps below.
>
> 1. *built it to byte code by py_compile.*
> 2. *execute it to check abspath.*
>
> But I got *2 results* when I execute it.I found the *results based on the
> path of script* followed by py_compile.
>
> Here is my script test.py :
>
> import os
> import inspect
> print
> os.path.dirname(os.path.abspath(inspect.getfile(inspect.currentframe())))
>
> Build it with py_compile, then got 2 results when I enter *different path
> of test.py*:
>
> *enter the folder and compile with only script name.*
>
> [~] cd /usr/local/bin/
> [/usr/local/bin/] python -m py_compile test.py
> [/usr/local/bin/] cd ~
> [~] python /usr/local/bin/test.pyc
> /home/UserXX
>
> *In other folder and compile with absolute script name.*
>
> [~] python -m py_compile /usr/local/bin/test.py
> [~] python /usr/local/bin/test.pyc
> /usr/local/bin
A code object has a co_filename attribute for use in creating
tracebacks. This path isn't necessarily fully qualified. Here are a
couple of examples using the built-in compile() function:
>>> compile('42', 'test.py', 'exec').co_filename
'test.py'
>>> compile('42', '/usr/local/bin/test.py', 'exec').co_filename
'/usr/local/bin/test.py'
py_compile.compile() does not normalize the filename.
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