I have a script that does this:
subprocess.Popen(['service', 'some_service', 'status'],
stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
When I run it from the command line it works fine. When I run it from
cron I get:
subprocess.Popen(['service', 'some_service', 'status'],
stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
File "/usr/lib64/python2.7/subprocess.py", line 711, in __init__
errread, errwrite)
File "/usr/lib64/python2.7/subprocess.py", line 1327, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
Anyone have any clue as to what file it's complaining about? Or how I
can debug this further?
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