Cheri Castro <blueyes7...@gmail.com> writes: > I've tried several variations but haven't been able to figure out why > my final if elif statement won't print.
The code you presented here does not have any ‘elif’ clause. Did you mean to show different code? > I tried using return, I tried using 1's and 0's rather than yes and > no. Not sure what the issue is. Please, help. Your questions are welcome here, but you may also be interested in <URL:http://mail.python.org/mailman/listinfo/tutor> the “tutor” discussion forum especially for Python beginners. > #This function will print how many yes answers the user has and a message > def correctAnswers(job, house, yard, time): > if correctAnswers == 'yes': > print ("Congratulations! You should get a puppy!") > else: > return "I'm sorry, you shouldn't get a puppy." The ‘if’ clause tests the value of ‘correctAnswers’. Where do you expect that value to come from? Nothing in the function ever sets a value to that name. On the other hand, the function never makes use of ‘job’, ‘house’, ‘yard’, or ‘time’. Why are those parameters to the function? -- \ “How wonderful that we have met with a paradox. Now we have | `\ some hope of making progress.” —Niels Bohr | _o__) | Ben Finney -- https://mail.python.org/mailman/listinfo/python-list
