Listing link urls

[Kishore Kumar Alajangi]

Hi,

I am facing an issue with listing specific urls inside web page,

https://economictimes.indiatimes.com/archive.cms

Page contains link urls by year and month vise,
Ex: /archive/year-2001,month-1.cms

I am able to list all required urls using the below code,

from bs4 import BeautifulSoup
import re, csv
import urllib.request
import scrapy
req = urllib.request.Request('http://economictimes.indiatimes.com/archive.cms',
headers={'User-Agent': 'Mozilla/5.0'})


links = []
totalPosts = []
url = "http://economictimes.indiatimes.com";
data = urllib.request.urlopen(req).read()
page = BeautifulSoup(data,'html.parser')

for link in page.findAll('a', href = re.compile('^/archive/')):
//retrieving urls starts with "archive"
    l = link.get('href')
    links.append(url+l)


with open("output.txt", "a") as f:
     for post in links:
         post = post + '\n'
         f.write(post)

*sample result in text file:*

http://economictimes.indiatimes.com/archive/year-2001,month-1.cmshttp://economictimes.indiatimes.com/archive/year-2001,month-2.cmshttp://economictimes.indiatimes.com/archive/year-2001,month-3.cmshttp://economictimes.indiatimes.com/archive/year-2001,month-4.cmshttp://economictimes.indiatimes.com/archive/year-2001,month-5.cmshttp://economictimes.indiatimes.com/archive/year-2001,month-6.cms


List of urls I am storing in a text file, From the month urls I want
to retrieve day urls starts with "/archivelist", I am using

the below code, but I am not getting any result, If I check with
inspect element the urls are available starting with /archivelist,

<a href="/archivelist/year-2001,month-3,starttime=36951.cms"></a>

Kindly help me where I am doing wrong.

from bs4 import BeautifulSoup
import re, csv
import urllib.request
import scrapy

file = open("output.txt", "r")


for i in file:

    urls = urllib.request.Request(i, headers={'User-Agent': 'Mozilla/5.0'})

    data1 = urllib.request.urlopen(urls).read()

    page1 = BeautifulSoup(data1, 'html.parser')

    for link1 in page1.findAll(href = re.compile('^/archivelist/')):

        l1 = link1.get('href')

        print(l1)


Thanks,

Kishore.
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