Dear All
This is my problem again , I tried to sort it out , but i couldn't , I
am reading data from file using readlines , my input like :
0 1 2 4
1 2 4
2 3
3 4
What i am doing is , starting with the first element in the first line (
which is 0 in this case )and do search in the other lines , if i found
another 0 , i will save (print out) all the elements except 0 , (in this
is case i have no 0 elsewhere) so i will print only 0. Now do search by
the 2nd element in the first line (which is 1 in this case) , in the 2nd
line we have 1 , so i should save(print out) all elements except 1 which
are 2 4 , and so on for the rest of the first line , and for the rest of
the file , my out put should be
0 1 2 4 2 1 4 3 4 1 2 3
1 2 3 4 3
2 3 4
3 4
I managed to do all these things , but i did it in the way that i am
reading my data as strings ( no space between numbers) something like
0124
124
23
34
what i would like to know or to do is , how can i deal with my data
after reading it as strings(i need the space between numbers) because i
had problem when dealing with number larger than 9 , example :
0 1 5 9
1 12 10
4 6 7
10 9
so , when i remove the space between numbers , i loose all my data , i
mean it will look like
0159
11210
467
509
This is my code :
def belong_to(x,a):
c=-1
for i in range(len(a)-1):
if x==int(a[i]):
c=i
return c
def list_belong(x,a): # This function to check if this line
c=-1 # line has been searched before or not
for i in range(len(a)):
if a[i]==x:
c=1
break
return c
x=0
occur=[]
in_file=open('data.dat','r')
out_file=open('result.dat','w')
fileList = in_file.readlines()
for k in fileList:
v=k
occur.append(k)
n=len(v)-1
for i in range(n):
temp=int(v[i])
print temp,
out_file.write(str(temp))
for line in fileList:
if v!=line:
if list_belong(line,occur)!=1:
if belong_to(temp,line) != -1:
j=belong_to(temp,line)
for i in range(len(line)-1):
if i!=j:
print line[i],
out_file.write(line[i])
print
out_file.write("\n")
out_file.close()
in_file.close()
Thank you all
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